-10y^2+33y-26=0

Solution for -10y^2+33y-26=0 equation:

-10y^2+33y-26=0

a = -10; b = 33; c = -26;
Δ = b2-4ac
Δ = 332-4·(-10)·(-26)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-7}{2*-10}=\frac{-40}{-20}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+7}{2*-10}=\frac{-26}{-20}
=1+3/10
$